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Algebra Find the Domain and Range F (x)=1/ (x^2) F (x) = 1 x2 F ( x) = 1 x 2 Set the denominator in 1 x2 1 x 2 equal to 0 0 to find where the expression is undefined x2 = 0 x 2 = 0 Solve for x x Tap for more steps Take the square root of both sides of the equation to eliminate the exponent on the left side x = ± √ 0 x = ± 0For domain under root should not be n egative quantity, 16−x2 ≥ 0 16≥ x2 Therefore, x ≤ 4 or x ≥ −4 Then, The domain−4,4 Range f (x) is maximum at x= 0,f (x)= 4 And f (x) is minimum at x= 4,f (x To find The domain and range of the real function Solution To find domain Equate the denominator to zero Denominator (3x)=0 x=3 This means at x=3 function is not defined And by definition of domain The domain is where the function is not defined Domain is Range Put f(x)=y Range is the set of value that correspond to domain F X 1 X 2 1 Find Domain And Range Of The Following Function Brainly In 30.find the domain and range of the function f(x)=(1)/(1-x^(2))

Maximize f(x,y)=xy on its boundary • One method is to solve one variable in terms of another The boundary is 2 = x2 y2,so we could solve and say y = ± p 2x2Thenwecanpluginfory to get f(x,y)=f(x)= ±x p 2x2 The boundary's critical points are precisely those values of x for which 0=f0(x)=⌥ 2(x2 1) p 2x2 This is only true when x = ±1X = 2 f − f 2 − 6 f 1 − f 1 , x = 1, (f = 0 and f ≤ 3 − 2 2 ) or f ≥ 2 2 3 f = 0 Steps Using the Quadratic Formula Steps for Completing the SquareOn what interval is f decreasing? Content Newton S Method If for all real numbers x f'(x) 0 and f''(x) 0

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